What is the limit as x approaches 0 of \sqrt[3]{1+x^2}-\sqrt[4]{1-2x} ?

The limit as x approaches 0 of \sqrt[3]{1+x^2}-\sqrt[4]{1-2x} is 0

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limit as x approaches 0 of \sqrt[3]{1+x^2}-\sqrt[4]{1-2x}

0

Solution steps

Plug in the value

x = 0

Simplify

= 0

\frac{d}{d x} (6.687 (0.931)^{x})

\frac{d y}{d x} = \frac{y ^{2} - x ^{2}}{y x}

\int e^{- s t} (2 - t) d t

\int \frac{x ^{3}}{x ^{4} - 6} d x

\frac{( 2 s + 3 )}{s ^{2} - 7}

What is the limit as x approaches 0 of \sqrt[3]{1+x^2}-\sqrt[4]{1-2x} ?
The limit as x approaches 0 of \sqrt[3]{1+x^2}-\sqrt[4]{1-2x} is 0