What is the limit as x approaches-1-of-1/(x+1) ?

The limit as x approaches-1-of-1/(x+1) is infinity

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limit as x approaches-1-of-1/(x+1)

x \to - 1 - lim (- \frac{1}{x + 1})

\infty

Solution steps

x \to - 1 - lim (- \frac{1}{x + 1})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to - 1 - lim (\frac{1}{x + 1})

For

x

approaching

- 1

from the left

, x < - 1 \Rightarrow x + 1 < 0

The denominator is a negative quantity approaching 0 from the left

= - (- \infty)

Simplify

= \infty

x \to - 3 lim (\frac{4 - x ^{2}}{x + 3})

θ \to π lim (θ sec (θ))

x \to 0 lim (\frac{x + sin ( 2 x )}{x})

x \to 0 lim (\frac{2}{x} - \frac{1}{e ^{x} - 1})

x \to 0 + lim ((x)^{s i n (x)})

What is the limit as x approaches-1-of-1/(x+1) ?
The limit as x approaches-1-of-1/(x+1) is infinity