What is the derivative of (3x^2+1^4) ?

The derivative of (3x^2+1^4) is 24x(3x^2+1)^3

What is the first derivative of (3x^2+1^4) ?

The first derivative of (3x^2+1^4) is 24x(3x^2+1)^3

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\frac{d}{d x} ((3 x^{2} + 1)^{4})

24 x (3 x^{2} + 1)^{3}

Solution steps

\frac{d}{d x} ((3 x^{2} + 1)^{4})

Apply the chain rule:

4 (3 x^{2} + 1)^{3} \frac{d}{d x} (3 x^{2} + 1)

= 4 (3 x^{2} + 1)^{3} \frac{d}{d x} (3 x^{2} + 1)

\frac{d}{d x} (3 x^{2} + 1) = 6 x

= 4 (3 x^{2} + 1)^{3} \cdot 6 x

Simplify

= 24 x (3 x^{2} + 1)^{3}

(2 x y + y^{2}) d x - 2 x^{2} d y = 0

\frac{d}{d x} (\frac{( x - 4 )}{x} + ln (\frac{x}{4}))

\frac{\partial}{\partial y} (\frac{x}{2 y ^{4}})

3 x + 1

\int \frac{1}{x ^{4} + x ^{2}} d x

What is the derivative of (3x^2+1^4) ?
The derivative of (3x^2+1^4) is 24x(3x^2+1)^3
What is the first derivative of (3x^2+1^4) ?
The first derivative of (3x^2+1^4) is 24x(3x^2+1)^3