What is the limit as x approaches 0+of x^2ln(x^3) ?

The limit as x approaches 0+of x^2ln(x^3) is 0

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limit as x approaches 0+of x^2ln(x^3)

x \to 0 + lim (x^{2} ln (x^{3}))

0

Solution steps

x \to 0 + lim (x^{2} ln (x^{3}))

ln (x^{3}) = 3 ln (x)

= x \to 0 + lim (x^{2} \cdot 3 ln (x))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 3 \cdot x \to 0 + lim (x^{2} ln (x))

Rewrite for L'Hopital

= 3 \cdot x \to 0 + lim (\frac{ln ( x )}{\frac{1}{x ^{2}}})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{2}{x ^{3}}})

= 3 \cdot x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{2}{x ^{3}}})

Simplify

\frac{\frac{1}{x}}{- \frac{2}{x ^{3}}} : - \frac{x ^{2}}{2}

= 3 \cdot x \to 0 + lim (- \frac{x ^{2}}{2})

Plug in the value

x = 0

= 3 (- \frac{0 ^{2}}{2})

Simplify

3 (- \frac{0 ^{2}}{2}) : 0

= 0

x \to \infty lim (\frac{x ^{2} - 5 x + 4}{4 x ^{2} + 2 x})

x \to \infty lim (- \frac{x}{0})

n \to \infty lim (e^{- n + 2})

h \to 0 lim (csc (h) - cot (h))

x \to - 3 lim ((4 x - 2 \cdot 3)^{2})

What is the limit as x approaches 0+of x^2ln(x^3) ?
The limit as x approaches 0+of x^2ln(x^3) is 0