What is (\partial)/(\partial x)(1-4/y+x) ?

The answer to (\partial)/(\partial x)(1-4/y+x) is 1

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(\partial)/(\partial x)(1-4/y+x)

\frac{\partial}{\partial x} (1 - \frac{4}{y} + x)

1

Solution steps

\frac{\partial}{\partial x} (1 - \frac{4}{y} + x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) - \frac{\partial}{\partial x} (\frac{4}{y}) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (\frac{4}{y}) = 0

\frac{\partial}{\partial x} (x) = 1

= 0 - 0 + 1

Simplify

= 1

θ

\frac{\partial}{\partial y} (2 z^{2} sin (y))

e^{s}

2 cos (7 x), sin (14 x)

500 q - \frac{q ^{2}}{ln ( q + 300 )}

What is (\partial)/(\partial x)(1-4/y+x) ?
The answer to (\partial)/(\partial x)(1-4/y+x) is 1