What is the limit as x approaches 0 of-1+ln(x)x ?

The limit as x approaches 0 of-1+ln(x)x is Does not exist

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limit as x approaches 0 of-1+ln(x)x

x \to 0 lim (- 1 + ln (x) x)

Does not exist

Solution steps

x \to 0 lim (- 1 + ln (x) x)

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (- 1 + ln (x) x) = - 1

x \to 0 - lim (- 1 + ln (x) x) =

Does not exist

= Does not exist

x \to \infty lim (\frac{sin ( 3 x )}{sin ( 4 x )})

x \to \frac{π}{4} lim (7 tan^{t a n (2 x)} (x))

x \to - 1 lim (2^{1 + l n (x)})

x \to a lim (\frac{x + 4}{x - 3})

x \to - 5 lim (17)

What is the limit as x approaches 0 of-1+ln(x)x ?
The limit as x approaches 0 of-1+ln(x)x is Does not exist