What is the limit as x approaches 0 of (e^x)/(e^x-1) ?

The limit as x approaches 0 of (e^x)/(e^x-1) is diverges

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limit as x approaches 0 of (e^x)/(e^x-1)

x \to 0 lim (\frac{e ^{x}}{e ^{x} - 1})

diverges

Solution steps

x \to 0 lim (\frac{e ^{x}}{e ^{x} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{e ^{x}}{e ^{x} - 1}) = \infty

x \to 0 - lim (\frac{e ^{x}}{e ^{x} - 1}) = - \infty

= diverges

x \to 0 lim (\frac{1}{1 - e ^{\frac{1}{x}}})

t \to 0 lim (\frac{e ^{7 t} - 1}{t})

x \to 0 lim (e^{x} cos (x))

x \to 2 lim (5 x + 2)

x \to - \infty lim (- 2 x)

What is the limit as x approaches 0 of (e^x)/(e^x-1) ?
The limit as x approaches 0 of (e^x)/(e^x-1) is diverges