What is the derivative of e^{1+x} ?

The derivative of e^{1+x} is e^{1+x}

What is the first derivative of e^{1+x} ?

The first derivative of e^{1+x} is e^{1+x}

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\frac{d}{d x} (e^{1 + x})

e^{1 + x}

Solution steps

\frac{d}{d x} (e^{1 + x})

Apply the chain rule:

e^{1 + x} \frac{d}{d x} (1 + x)

= e^{1 + x} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= e^{1 + x} \cdot 1

Simplify

= e^{1 + x}

\int sec (2 x) tan^{5} (2 x) d x

\int (e^{x y}) d y

(\frac{1}{tan ( x )})^{^{'}}

lo g_{5} (5 x^{3} + 2 x + 5)

y^{^{'}} = tan (t) y - 5 t

What is the derivative of e^{1+x} ?
The derivative of e^{1+x} is e^{1+x}
What is the first derivative of e^{1+x} ?
The first derivative of e^{1+x} is e^{1+x}