What is the limit as x approaches 0 of ((1-x)^2-1)/x ?

The limit as x approaches 0 of ((1-x)^2-1)/x is -2

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limit as x approaches 0 of ((1-x)^2-1)/x

x \to 0 lim (\frac{( 1 - x ) ^{2} - 1}{x})

- 2

Solution steps

x \to 0 lim (\frac{( 1 - x ) ^{2} - 1}{x})

Simplify

\frac{( 1 - x ) ^{2} - 1}{x} : x - 2

= x \to 0 lim (x - 2)

Plug in the value

x = 0

= 0 - 2

Simplify

= - 2

x \to \frac{π}{2} lim (\frac{cos ( x )}{x})

x \to \infty lim (\frac{2 x - 1}{2 ^{x}})

x \to 3 lim (x + 5)

x \to \infty lim (ln (x + 2) - ln (x + 3))

x \to \infty lim (- 3 \cdot x)

What is the limit as x approaches 0 of ((1-x)^2-1)/x ?
The limit as x approaches 0 of ((1-x)^2-1)/x is -2