What is the limit as x approaches 0 of sin^2(2x) ?

The limit as x approaches 0 of sin^2(2x) is 0

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limit as x approaches 0 of sin^2(2x)

x \to 0 lim (sin^{2} (2 x))

0

Solution steps

x \to 0 lim (sin^{2} (2 x))

Plug in the value

x = 0

= sin^{2} (2 \cdot 0)

Simplify

sin^{2} (2 \cdot 0) : 0

= 0

x \to \infty lim ((1 - \frac{3}{x})^{x - 2})

x \to 0 + lim (x^{4} sin (\frac{1}{x}))

x \to 0 lim ((cos (x) - sin (x))^{\frac{1}{x}})

x \to - \infty lim (\frac{x}{4})

y \to 0 lim (y + y^{3} sin (\frac{x}{y}))

What is the limit as x approaches 0 of sin^2(2x) ?
The limit as x approaches 0 of sin^2(2x) is 0