What is the limit as x approaches-1 of (ln(x+1))/x ?

The limit as x approaches-1 of (ln(x+1))/x is Does not exist

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limit as x approaches-1 of (ln(x+1))/x

x \to - 1 lim (\frac{ln ( x + 1 )}{x})

Does not exist

Solution steps

x \to - 1 lim (\frac{ln ( x + 1 )}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{ln ( x + 1 )}{x}) = \infty

x \to - 1 - lim (\frac{ln ( x + 1 )}{x}) =

Does not exist

= Does not exist

x \to \infty lim (e^{- x} sin (e^{x}))

x \to 3 lim (\frac{2 x ^{2} - 10 x + 12}{x ^{2} + 3 x - 10})

x \to 0 lim (\frac{5 x + 3}{x})

x \to 4 + lim ((4 - x) \cdot ln (x - 4))

x \to 1 lim (1 - x + ln (x))

What is the limit as x approaches-1 of (ln(x+1))/x ?
The limit as x approaches-1 of (ln(x+1))/x is Does not exist