What is (\partial ^2)/(\partial x\partial y)(ln(x^2+y^3)) ?

The answer to (\partial ^2)/(\partial x\partial y)(ln(x^2+y^3)) is -(6xy^2)/((x^2+y^3)^2)

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(\partial ^2)/(\partial x\partial y)(ln(x^2+y^3))

\frac{\partial ^{2}}{\partial x \partial y} (ln (x^{2} + y^{3}))

- \frac{6 x y ^{2}}{( x ^{2} + y ^{3} ) ^{2}}

Solution steps

\frac{\partial ^{2}}{\partial x \partial y} (ln (x^{2} + y^{3}))

\frac{\partial}{\partial x} (ln (x^{2} + y^{3})) = \frac{2 x}{x ^{2} + y ^{3}}

= \frac{\partial}{\partial y} (\frac{2 x}{x ^{2} + y ^{3}})

\frac{\partial}{\partial y} (\frac{2 x}{x ^{2} + y ^{3}}) = - \frac{6 x y ^{2}}{( x ^{2} + y ^{3} ) ^{2}}

= - \frac{6 x y ^{2}}{( x ^{2} + y ^{3} ) ^{2}}

y^{^{''}} + 36 y = 0, y (0) = 0, y^{^{'}} (0) = 1

2 - 3 x

\int 4 - y^{2} d y

n = 1 \sum \infty \frac{- 1 ^{n}}{n ^{5}}

\int \frac{2 ( 1 + x )}{x ( 2 + x )} d x

What is (\partial ^2)/(\partial x\partial y)(ln(x^2+y^3)) ?
The answer to (\partial ^2)/(\partial x\partial y)(ln(x^2+y^3)) is -(6xy^2)/((x^2+y^3)^2)