What is the limit as x approaches pi/2 of 7cos(-5x)sec(-7x) ?

The limit as x approaches pi/2 of 7cos(-5x)sec(-7x) is -5

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limit as x approaches pi/2 of 7cos(-5x)sec(-7x)

x \to \frac{π}{2} lim (7 cos (- 5 x) sec (- 7 x))

- 5

Solution steps

x \to \frac{π}{2} lim (7 cos (- 5 x) sec (- 7 x))

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to \frac{π}{2} - lim (7 cos (- 5 x) sec (- 7 x)) = - 5

x \to \frac{π}{2} + lim (7 cos (- 5 x) sec (- 7 x)) = - 5

= - 5

x \to \infty lim (\frac{( 10 - 6 x ^{2} )}{5 + 3 e ^{x}})

x \to 0 lim (\frac{arccot ( x )}{x})

x \to 0 lim (\frac{sin ( x ) - arctan ( x )}{x ^{2} ln ( 1 + x )})

x \to 5 lim (x + 5)

x \to 1 lim (\frac{3 x + 2}{1 - x})

What is the limit as x approaches pi/2 of 7cos(-5x)sec(-7x) ?
The limit as x approaches pi/2 of 7cos(-5x)sec(-7x) is -5