What is the limit as x approaches 0 of xe^{1/x}-x ?

The limit as x approaches 0 of xe^{1/x}-x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of xe^{1/x}-x

x \to 0 lim (x e^{\frac{1}{x}} - x)

diverges

Solution steps

x \to 0 lim (x e^{\frac{1}{x}} - x)

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x e^{\frac{1}{x}} - x) = \infty

x \to 0 - lim (x e^{\frac{1}{x}} - x) = 0

= diverges

x \to - \infty lim (- 2^{x})

x \to 0 lim (\frac{( 3 - x ) ^{2} - 9}{x})

x \to 3 lim (10 - 4 x)

x \to \frac{π}{2} lim (\frac{tan ( x )}{\frac{3}{( 2 x - π )}})

x \to 0 lim (1 - sin (x))

What is the limit as x approaches 0 of xe^{1/x}-x ?
The limit as x approaches 0 of xe^{1/x}-x is diverges