What is the limit as x approaches 0 of 1/(e^{1/x)} ?

The limit as x approaches 0 of 1/(e^{1/x)} is diverges

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limit as x approaches 0 of 1/(e^{1/x)}

x \to 0 lim (\frac{1}{e ^{\frac{1}{x}}})

diverges

Solution steps

x \to 0 lim (\frac{1}{e ^{\frac{1}{x}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{e ^{\frac{1}{x}}}) = 0

x \to 0 - lim (\frac{1}{e ^{\frac{1}{x}}}) = \infty

= diverges

\frac{\partial}{\partial z} (\frac{x}{z})

g (x) = ln (x e^{- 7 x})

\frac{\partial}{\partial y} (x^{2} y^{\frac{1}{3}})

\int \frac{u}{u ^{2} + 1} d u

x \to 0 lim (\frac{ln ( \frac{1 + x}{1 - x} ) - 2 x}{x - sin ( x )})

What is the limit as x approaches 0 of 1/(e^{1/x)} ?
The limit as x approaches 0 of 1/(e^{1/x)} is diverges