What is the sum from n=0 to infinity of 2*5^n ?

The sum from n=0 to infinity of 2*5^n is diverges

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sum from n=0 to infinity of 2*5^n

n = 0 \sum \infty 2 \cdot 5^{n}

diverges

Solution steps

n = 0 \sum \infty 2 \cdot 5^{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 0 \sum \infty 5^{n}

Apply Series Geometric Test:

diverges

= 2 diverges

= diverges

y^{^{'}} = \frac{y}{a} - 1

x \to 3 lim (2 3 x)

\int 5 e^{x} + 3 sin (x) d x

\int \frac{1}{x 4 x ^{2} + 49} d x

(7, - 2), (- 7, 2)

What is the sum from n=0 to infinity of 2*5^n ?
The sum from n=0 to infinity of 2*5^n is diverges