What is the derivative of (x-2^3) ?

The derivative of (x-2^3) is 3(x-2)^2

What is the first derivative of (x-2^3) ?

The first derivative of (x-2^3) is 3(x-2)^2

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\frac{d}{d x} ((x - 2)^{3})

3 (x - 2)^{2}

Solution steps

\frac{d}{d x} ((x - 2)^{3})

Apply the chain rule:

3 (x - 2)^{2} \frac{d}{d x} (x - 2)

= 3 (x - 2)^{2} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 3 (x - 2)^{2} \cdot 1

Simplify

= 3 (x - 2)^{2}

- \frac{1}{s ^{2}} e^{- 5 s} + \frac{1}{s ^{2}}

\int \frac{3 x ^{2} - 8 x - 9}{x ^{3} - 4 x ^{2} - 9 x + 36} d x

x \to \infty lim (1 5^{x})

\int (3 x^{2} - 5 x)^{3} (6 x - 5) d x

y (9 - y) - \frac{81}{4} = \frac{d y}{d t}, y (0) = 4

What is the derivative of (x-2^3) ?
The derivative of (x-2^3) is 3(x-2)^2
What is the first derivative of (x-2^3) ?
The first derivative of (x-2^3) is 3(x-2)^2