What is the limit as x approaches 0+of 1+e^{-1/x} ?

The limit as x approaches 0+of 1+e^{-1/x} is 1

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limit as x approaches 0+of 1+e^{-1/x}

x \to 0 + lim (1 + e^{- \frac{1}{x}})

1

Solution steps

x \to 0 + lim (1 + e^{- \frac{1}{x}})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (1) + x \to 0 + lim (e^{- \frac{1}{x}})

x \to 0 + lim (1) = 1

x \to 0 + lim (e^{- \frac{1}{x}}) = 0

= 1 + 0

Simplify

= 1

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What is the limit as x approaches 0+of 1+e^{-1/x} ?
The limit as x approaches 0+of 1+e^{-1/x} is 1