What is the solution for t(dy)/(dt)=t^3+14t^3y ?

The solution for t(dy)/(dt)=t^3+14t^3y is y=(e^{(14t^3+c_{1})/3})/(14)-1/14

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t(dy)/(dt)=t^3+14t^3y

t \frac{d y}{d t} = t^{3} + 14 t^{3} y

y = \frac{e ^{\frac{14 t ^{3} + c _{1}}{3}}}{14} - \frac{1}{14}

Solution steps

t \frac{d y}{d t} = t^{3} + 14 t^{3} y

Solve separable ODE:

y = \frac{e ^{\frac{14 t ^{3} + c _{1}}{3}}}{14} - \frac{1}{14}

y = \frac{e ^{\frac{14 t ^{3} + c _{1}}{3}}}{14} - \frac{1}{14}

\frac{d}{d x} (- \frac{y}{x ^{2} + y ^{2} + 1})

\frac{1 - ln ( x )}{2 x ^{2}}

x \to 1 + lim ((x - 1)^{x - 1})

\frac{1}{s ^{2} + 6 s + 10}

\frac{\partial}{\partial y} (- 2 y)

What is the solution for t(dy)/(dt)=t^3+14t^3y ?
The solution for t(dy)/(dt)=t^3+14t^3y is y=(e^{(14t^3+c_{1})/3})/(14)-1/14