What is the limit as x approaches 0 of (e^x)/(2x) ?

The limit as x approaches 0 of (e^x)/(2x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (e^x)/(2x)

x \to 0 lim (\frac{e ^{x}}{2 x})

diverges

Solution steps

x \to 0 lim (\frac{e ^{x}}{2 x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{e ^{x}}{2 x}) = \infty

x \to 0 - lim (\frac{e ^{x}}{2 x}) = - \infty

= diverges

x \to - 2 + lim (\frac{x ^{2}}{x ^{2} - 4})

x \to - 1 - lim (\frac{x - 1}{x ^{2} - 1})

x \to 0 + lim (x^{l n (1 + x)})

x \to - 3 lim (\frac{5}{( x + 3 ) ^{3}})

x \to 0 lim (7 x ln (x))

What is the limit as x approaches 0 of (e^x)/(2x) ?
The limit as x approaches 0 of (e^x)/(2x) is diverges