What is the limit as x approaches-1 of e^{x/(x+1)} ?

The limit as x approaches-1 of e^{x/(x+1)} is diverges

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limit as x approaches-1 of e^{x/(x+1)}

x \to - 1 lim (e^{\frac{x}{x + 1}})

diverges

Solution steps

x \to - 1 lim (e^{\frac{x}{x + 1}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (e^{\frac{x}{x + 1}}) = 0

x \to - 1 - lim (e^{\frac{x}{x + 1}}) = \infty

= diverges

x \to 3 lim (\frac{3 - x}{x - 3})

x \to - \frac{π}{2} - lim (- 2 x - \frac{π}{2})

t \to 0 + lim (\frac{2 sin ( 4 t )}{t})

x \to 0 + lim ((2 x)^{x})

x \to \frac{π}{2} lim (\frac{1}{tan ( x )})

What is the limit as x approaches-1 of e^{x/(x+1)} ?
The limit as x approaches-1 of e^{x/(x+1)} is diverges