What is (\partial)/(\partial x)((x+y)/(y+1)) ?

The answer to (\partial)/(\partial x)((x+y)/(y+1)) is 1/(y+1)

Popular >

(\partial)/(\partial x)((x+y)/(y+1))

\frac{\partial}{\partial x} (\frac{x + y}{y + 1})

\frac{1}{y + 1}

Solution steps

\frac{\partial}{\partial x} (\frac{x + y}{y + 1})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y + 1} \frac{\partial}{\partial x} (x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{y + 1} (\frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{y + 1} (1 + 0)

Simplify

= \frac{1}{y + 1}

x \to 3 lim (x + 1)

\frac{d y}{d x}, y^{4} = x^{9}

\frac{d}{d x} (e^{x^{2} + 5 x})

(- 2.1) (- 1.7)

\int \frac{x ^{2}}{x ^{6} + 3 x ^{3} + 2} d x

What is (\partial)/(\partial x)((x+y)/(y+1)) ?
The answer to (\partial)/(\partial x)((x+y)/(y+1)) is 1/(y+1)