What is the derivative of sec^2(2x+4*2) ?

The derivative of sec^2(2x+4*2) is 8sec^2(2x+4)tan(2x+4)

What is the first derivative of sec^2(2x+4*2) ?

The first derivative of sec^2(2x+4*2) is 8sec^2(2x+4)tan(2x+4)

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\frac{d}{d x} (sec^{2} (2 x + 4) \cdot 2)

8 sec^{2} (2 x + 4) tan (2 x + 4)

Solution steps

\frac{d}{d x} (sec^{2} (2 x + 4) \cdot 2)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sec^{2} (2 x + 4))

Apply the chain rule:

2 sec (2 x + 4) \frac{d}{d x} (sec (2 x + 4))

= 2 sec (2 x + 4) \frac{d}{d x} (sec (2 x + 4))

\frac{d}{d x} (sec (2 x + 4)) = sec (2 x + 4) tan (2 x + 4) \cdot 2

= 2 \cdot 2 sec (2 x + 4) sec (2 x + 4) tan (2 x + 4) \cdot 2

Simplify

2 \cdot 2 sec (2 x + 4) sec (2 x + 4) tan (2 x + 4) \cdot 2 : 8 sec^{2} (2 x + 4) tan (2 x + 4)

= 8 sec^{2} (2 x + 4) tan (2 x + 4)

f (x) = \frac{f ( x )}{x ^{7}}

5 x^{3} + 2 x^{2} + 3

x \to \infty lim (co x (x))

f (x) = x^{2} + x - 3, at x = 4

\frac{\partial}{\partial s} (- 5 s^{2} t)

What is the derivative of sec^2(2x+4*2) ?
The derivative of sec^2(2x+4*2) is 8sec^2(2x+4)tan(2x+4)
What is the first derivative of sec^2(2x+4*2) ?
The first derivative of sec^2(2x+4*2) is 8sec^2(2x+4)tan(2x+4)