What is the derivative of f(x)=((2x+1))/(x+3) ?

The derivative of f(x)=((2x+1))/(x+3) is 5/((x+3)^2)

What is the first derivative of f(x)=((2x+1))/(x+3) ?

The first derivative of f(x)=((2x+1))/(x+3) is 5/((x+3)^2)

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derivative of

f (x) = \frac{( 2 x + 1 )}{x + 3}

\frac{5}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x + 1}{x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x + 1 ) ( x + 3 ) - \frac{d}{d x} ( x + 3 ) ( 2 x + 1 )}{( x + 3 ) ^{2}}

\frac{d}{d x} (2 x + 1) = 2

\frac{d}{d x} (x + 3) = 1

= \frac{2 ( x + 3 ) - 1 \cdot ( 2 x + 1 )}{( x + 3 ) ^{2}}

Simplify

\frac{2 ( x + 3 ) - 1 \cdot ( 2 x + 1 )}{( x + 3 ) ^{2}} : \frac{5}{( x + 3 ) ^{2}}

= \frac{5}{( x + 3 ) ^{2}}

x = - 1, x = 2, y = x^{3} - 1, y = 0

\int \frac{4 x + 6}{( x ^{2} + 3 ) ( x + 1 )} d x

\int_{0}^{5} ∣ 2 x - 6 ∣ d x

\frac{x + 1}{x - 1}

\int \frac{1}{x n x} d x

What is the derivative of f(x)=((2x+1))/(x+3) ?
The derivative of f(x)=((2x+1))/(x+3) is 5/((x+3)^2)
What is the first derivative of f(x)=((2x+1))/(x+3) ?
The first derivative of f(x)=((2x+1))/(x+3) is 5/((x+3)^2)