What is the limit as x approaches 4 of ax^2+bx+4 ?

The limit as x approaches 4 of ax^2+bx+4 is 16a+4b+4

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limit as x approaches 4 of ax^2+bx+4

x \to 4 lim (a x^{2} + b x + 4)

16 a + 4 b + 4

Solution steps

x \to 4 lim (a x^{2} + b x + 4)

Plug in the value

x = 4

= a \cdot 4^{2} + b \cdot 4 + 4

Simplify

= 16 a + 4 b + 4

x \to 0 lim (x x)

x \to \infty lim ((ln (x))^{\frac{3}{x}})

x \to a lim ([f (x) + g (x)])

x \to \infty lim (x^{\frac{8}{l n ( x )}})

x \to e lim (\frac{1}{x ln ( x - 1 )})

What is the limit as x approaches 4 of ax^2+bx+4 ?
The limit as x approaches 4 of ax^2+bx+4 is 16a+4b+4