What is the derivative of 2x^2-4x+4 ?

The derivative of 2x^2-4x+4 is 4x-4

What is the first derivative of 2x^2-4x+4 ?

The first derivative of 2x^2-4x+4 is 4x-4

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\frac{d}{d x} (2 x^{2} - 4 x + 4)

4 x - 4

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (4) = 0

= 4 x - 4 + 0

Simplify

= 4 x - 4

- 8 x^{2} + 500 x + 140

\frac{2 x + 3}{2 x - 3}

\int (2 - x) 4 - x^{2} d x

\int \frac{ln ( x ^{2} )}{x ^{2}} d x

\int_{0}^{2} 9 x^{3} x^{2} + 4 d x

What is the derivative of 2x^2-4x+4 ?
The derivative of 2x^2-4x+4 is 4x-4
What is the first derivative of 2x^2-4x+4 ?
The first derivative of 2x^2-4x+4 is 4x-4