What is the derivative of 2x^2-x-3 ?

The derivative of 2x^2-x-3 is 4x-1

What is the first derivative of 2x^2-x-3 ?

The first derivative of 2x^2-x-3 is 4x-1

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derivative of

2 x^{2} - x - 3

4 x - 1

Solution steps

\frac{d}{d x} (2 x^{2} - x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x} - \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 4 x - 1 - 0

Simplify

= 4 x - 1

\int \frac{y ^{2} - b ^{2}}{y ^{2}} d y

\int \frac{e ^{x}}{1 + e ^{x}} d x

x \to 8 lim (\frac{( 1 )}{( x - 8 )})

\frac{\partial}{\partial y} (arcsin (x y))

\int \frac{1}{x ^{2} - 4 x + 9} d x

What is the derivative of 2x^2-x-3 ?
The derivative of 2x^2-x-3 is 4x-1
What is the first derivative of 2x^2-x-3 ?
The first derivative of 2x^2-x-3 is 4x-1