What is the limit as x approaches 0+of ln(x)+1 ?

The limit as x approaches 0+of ln(x)+1 is -infinity

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limit as x approaches 0+of ln(x)+1

x \to 0 + lim (ln (x) + 1)

- \infty

Solution steps

x \to 0 + lim (ln (x) + 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (ln (x)) + x \to 0 + lim (1)

x \to 0 + lim (ln (x)) = - \infty

x \to 0 + lim (1) = 1

= - \infty + 1

Apply Infinity Property:

- \infty + c = - \infty

= - \infty

x \to 8 - lim (\frac{x + 5}{x - 8})

x \to \infty lim (0, + x)

x \to 0 + lim ((1 + 3 x)^{\frac{4}{x}})

x \to 0 lim (x + [x])

x \to 10 lim (20)

What is the limit as x approaches 0+of ln(x)+1 ?
The limit as x approaches 0+of ln(x)+1 is -infinity