What is the integral from 0 to 1 of \sqrt[3]{x} ?

The integral from 0 to 1 of \sqrt[3]{x} is 3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of \sqrt[3]{x}

\frac{3}{4}

Decimal Notation

0.75

Solution steps

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{0}^{1}

= [\frac{3}{4} x^{\frac{4}{3}}]_{0}^{1}

Compute the boundaries:

\frac{3}{4}

= \frac{3}{4}

\int \frac{2 x + 5}{3 x - 1} d x

\frac{d}{d x} ((\frac{1}{3 x + 1})^{4})

\frac{4}{s ^{2} + 9}

\frac{d y}{d x} = 1 - 2 y, y (0) = 0

\int 11 sin^{5} (x) d x

What is the integral from 0 to 1 of \sqrt[3]{x} ?
The integral from 0 to 1 of \sqrt[3]{x} is 3/4