What is the limit as x approaches-1 of ln(x+2) ?

The limit as x approaches-1 of ln(x+2) is 0

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limit as x approaches-1 of ln(x+2)

x \to - 1 lim (ln (x + 2))

0

Solution steps

x \to - 1 lim (ln (x + 2))

Plug in the value

x = - 1

= ln (- 1 + 2)

Simplify

ln (- 1 + 2) : 0

= 0

x \to \infty lim (e^{k x})

n \to \infty lim (\frac{cos ( n )}{n ^{2}})

x \to π lim (tan (\frac{x}{4}))

x \to 0 lim (x tan (\frac{π}{2} - x))

x \to 2 - lim (\frac{- 3}{x - 2})

What is the limit as x approaches-1 of ln(x+2) ?
The limit as x approaches-1 of ln(x+2) is 0