What is the limit as x approaches-1 of 1/((1+x)^2) ?

The limit as x approaches-1 of 1/((1+x)^2) is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-1 of 1/((1+x)^2)

x \to - 1 lim (\frac{1}{( 1 + x ) ^{2}})

\infty

Solution steps

x \to - 1 lim (\frac{1}{( 1 + x ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 1 - lim (\frac{1}{( 1 + x ) ^{2}}) = \infty

x \to - 1 + lim (\frac{1}{( 1 + x ) ^{2}}) = \infty

= \infty

x \to - 2 lim (3 x^{3} + y)

x \to - 3 - lim (\frac{1}{( x + 3 ) ^{5}})

x \to \frac{π}{3} lim (cot (x) + 2)

x \to 0 lim (x ln (4 x))

x \to 3 lim (x^{3} - 27)

What is the limit as x approaches-1 of 1/((1+x)^2) ?
The limit as x approaches-1 of 1/((1+x)^2) is infinity