What is the derivative of y=3e^{-x}+e^{4x} ?

The derivative of y=3e^{-x}+e^{4x} is -3e^{-x}+e^{4x}*4

What is the first derivative of y=3e^{-x}+e^{4x} ?

The first derivative of y=3e^{-x}+e^{4x} is -3e^{-x}+e^{4x}*4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 3 e^{- x} + e^{4 x}

- 3 e^{- x} + e^{4 x} \cdot 4

Solution steps

\frac{d}{d x} (3 e^{- x} + e^{4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 e^{- x}) + \frac{d}{d x} (e^{4 x})

\frac{d}{d x} (3 e^{- x}) = - 3 e^{- x}

\frac{d}{d x} (e^{4 x}) = e^{4 x} \cdot 4

= - 3 e^{- x} + e^{4 x} \cdot 4

\int x x d x

\int sin (x) (x^{2} + x) d x

\frac{\partial}{\partial x} (x cos (y^{2}) + yz)

\int \frac{x ^{2} + 1}{x ^{2} - 3} d x

x \to 0 lim (1 - x^{3})

What is the derivative of y=3e^{-x}+e^{4x} ?
The derivative of y=3e^{-x}+e^{4x} is -3e^{-x}+e^{4x}*4
What is the first derivative of y=3e^{-x}+e^{4x} ?
The first derivative of y=3e^{-x}+e^{4x} is -3e^{-x}+e^{4x}*4