What is the limit as x approaches 1 of-ln(1-x) ?

The limit as x approaches 1 of-ln(1-x) is Does not exist

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limit as x approaches 1 of-ln(1-x)

x \to 1 lim (- ln (1 - x))

Does not exist

Solution steps

x \to 1 lim (- ln (1 - x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (- ln (1 - x)) =

Does not exist

x \to 1 - lim (- ln (1 - x)) = \infty

= Does not exist

x \to 0 lim (x ln (tan (x)))

x \to 0 lim (\frac{x ^{2}}{x ^{2} - 1})

x \to 3 - lim (\frac{x + 4}{x + 3})

x \to 2 + lim (\frac{1}{4 - x ^{2}})

x \to 0 lim (\frac{\frac{1}{x - 1} + 1}{x})

What is the limit as x approaches 1 of-ln(1-x) ?
The limit as x approaches 1 of-ln(1-x) is Does not exist