What is the limit as x approaches-4 of 1/((x+4)^2) ?

The limit as x approaches-4 of 1/((x+4)^2) is infinity

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limit as x approaches-4 of 1/((x+4)^2)

x \to - 4 lim (\frac{1}{( x + 4 ) ^{2}})

\infty

Solution steps

x \to - 4 lim (\frac{1}{( x + 4 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 4 - lim (\frac{1}{( x + 4 ) ^{2}}) = \infty

x \to - 4 + lim (\frac{1}{( x + 4 ) ^{2}}) = \infty

= \infty

x \to 0 + lim (x^{x^{x}} - 1)

x \to \frac{π}{2} lim ((2 x - π) tan (x))

x \to 1 + lim (tan (x - 1))

x \to 4 lim (\frac{2 x - 4}{x - 1})

x \to - \infty lim (- (x)^{2})

What is the limit as x approaches-4 of 1/((x+4)^2) ?
The limit as x approaches-4 of 1/((x+4)^2) is infinity