What is the limit as x approaches-2 of 1/(4-x^2) ?

The limit as x approaches-2 of 1/(4-x^2) is diverges

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limit as x approaches-2 of 1/(4-x^2)

x \to - 2 lim (\frac{1}{4 - x ^{2}})

diverges

Solution steps

x \to - 2 lim (\frac{1}{4 - x ^{2}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 2 + lim (\frac{1}{4 - x ^{2}}) = \infty

x \to - 2 - lim (\frac{1}{4 - x ^{2}}) = - \infty

= diverges

x \to 4 lim (\frac{3 x ^{2} - 17 x + 20}{4 x ^{2} - 25 + 36})

x \to 0 + lim (\frac{e ^{- x}}{x})

x \to \infty lim (\frac{1.5 x}{3 x ^{2}})

x \to 3 lim (4 x - 7)

x \to 3 lim (4 x - 1)

What is the limit as x approaches-2 of 1/(4-x^2) ?
The limit as x approaches-2 of 1/(4-x^2) is diverges