What is (\partial)/(\partial x)(tan(x+y)) ?

The answer to (\partial)/(\partial x)(tan(x+y)) is sec^2(x+y)

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(\partial)/(\partial x)(tan(x+y))

\frac{\partial}{\partial x} (tan (x + y))

sec^{2} (x + y)

Solution steps

\frac{\partial}{\partial x} (tan (x + y))

Treat

y

as a constant

Apply the chain rule:

sec^{2} (x + y) \frac{\partial}{\partial x} (x + y)

= sec^{2} (x + y) \frac{\partial}{\partial x} (x + y)

\frac{\partial}{\partial x} (x + y) = 1

= sec^{2} (x + y) \cdot 1

Simplify

= sec^{2} (x + y)

\int ln (r^{2}) d r

y^{^{'}} = 5 y sin (4 x)

\int \frac{- 1}{x} d x

\frac{1}{2 s - 5}

\frac{d}{d x} (ln (sin (3 x)))

What is (\partial)/(\partial x)(tan(x+y)) ?
The answer to (\partial)/(\partial x)(tan(x+y)) is sec^2(x+y)