What is the limit as x approaches 0 of e^{(x-1)/x} ?

The limit as x approaches 0 of e^{(x-1)/x} is diverges

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limit as x approaches 0 of e^{(x-1)/x}

x \to 0 lim (e^{\frac{x - 1}{x}})

diverges

Solution steps

x \to 0 lim (e^{\frac{x - 1}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (e^{\frac{x - 1}{x}}) = 0

x \to 0 - lim (e^{\frac{x - 1}{x}}) = \infty

= diverges

x \to 0 lim (\frac{2 x}{x ^{2} + x})

x \to \infty lim (- x^{2} e^{x})

x \to 2 lim (\frac{1 - 4 x}{x + 3})

h \to 0 lim (\frac{ln ( 2 e + h ) - ln ( 2 e )}{h})

x \to 0 lim (\frac{e ^{x} - cos ( x )}{ln ( 1 + x )})

What is the limit as x approaches 0 of e^{(x-1)/x} ?
The limit as x approaches 0 of e^{(x-1)/x} is diverges