What is the limit as x approaches 0+of x^{sin(2x)} ?

The limit as x approaches 0+of x^{sin(2x)} is 1

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limit as x approaches 0+of x^{sin(2x)}

x \to 0 + lim (x^{s i n (2 x)})

1

Solution steps

x \to 0 + lim (x^{s i n (2 x)})

Apply exponent rules

= x \to 0 + lim (e^{s i n (2 x) l n (x)})

Apply the Limit Chain Rule:

1

= 1

y = 6 + 5 x^{2} - 2 x^{3}

\frac{d}{d x} (sin (2 x) cos (3 x))

\frac{\partial}{\partial x} (z^{x y})

y^{^{''}} + 9 y = 4 csc^{2} (3 x)

f (x) = x^{3} - 3 x + 2, (3, 20)

What is the limit as x approaches 0+of x^{sin(2x)} ?
The limit as x approaches 0+of x^{sin(2x)} is 1