What is the limit as x approaches 0 of (2x^2-5x)/x ?

The limit as x approaches 0 of (2x^2-5x)/x is -5

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limit as x approaches 0 of (2x^2-5x)/x

x \to 0 lim (\frac{2 x ^{2} - 5 x}{x})

- 5

Solution steps

x \to 0 lim (\frac{2 x ^{2} - 5 x}{x})

Simplify

\frac{2 x ^{2} - 5 x}{x} : 2 x - 5

= x \to 0 lim (2 x - 5)

Plug in the value

x = 0

= 2 \cdot 0 - 5

Simplify

= - 5

x \to \infty lim (x - x^{2} - 16)

x \to 4 - lim (\frac{( x ^{2} - 6 x + 8 )}{x ^{2} - 9 x + 20})

x \to 0 + lim (∣ x ∣^{x})

x \to 1 lim (\frac{x ^{2}}{x + 1})

x \to 5 lim (\frac{- 1}{x - 5})

What is the limit as x approaches 0 of (2x^2-5x)/x ?
The limit as x approaches 0 of (2x^2-5x)/x is -5