What is the limit as x approaches-infinity of 2+5e^x ?

The limit as x approaches-infinity of 2+5e^x is 2

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limit as x approaches-infinity of 2+5e^x

x \to - \infty lim (2 + 5 e^{x})

2

Solution steps

x \to - \infty lim (2 + 5 e^{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to - \infty lim (2) + x \to - \infty lim (5 e^{x})

x \to - \infty lim (2) = 2

x \to - \infty lim (5 e^{x}) = 0

= 2 + 0

Simplify

= 2

x \to 0 + lim (x^{3 x})

x \to 0 lim ((e^{x} - 1) cot (x))

x \to 2 π lim (e^{c o s (x)})

x \to 3 lim (5 x^{2} + 4)

x \to 3 - lim (\frac{x + 3}{x - 3})

What is the limit as x approaches-infinity of 2+5e^x ?
The limit as x approaches-infinity of 2+5e^x is 2