What is the limit as x approaches 0 of 0/(x-e^x+1) ?

The limit as x approaches 0 of 0/(x-e^x+1) is 0

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limit as x approaches 0 of 0/(x-e^x+1)

x \to 0 lim (\frac{0}{x - e ^{x} + 1})

0

Solution steps

x \to 0 lim (\frac{0}{x - e ^{x} + 1})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{0}{x - e ^{x} + 1}) = 0

x \to 0 + lim (\frac{0}{x - e ^{x} + 1}) = 0

= 0

x \to - 1 - lim (\frac{x ^{3}}{x ^{2} - 1})

x \to 1 - lim (ln (x) \cdot ln (1 - x))

x \to 3 lim (x^{2} - x)

z \to 2 lim (\frac{z ^{3} - 8}{z - 2})

x \to \frac{π}{2} + lim (\frac{tan ( x )}{x})

What is the limit as x approaches 0 of 0/(x-e^x+1) ?
The limit as x approaches 0 of 0/(x-e^x+1) is 0