What is the limit as x approaches 1 of 1/(ln(x))-1/x ?

The limit as x approaches 1 of 1/(ln(x))-1/x is diverges

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limit as x approaches 1 of 1/(ln(x))-1/x

x \to 1 lim (\frac{1}{ln ( x )} - \frac{1}{x})

diverges

Solution steps

x \to 1 lim (\frac{1}{ln ( x )} - \frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{1}{ln ( x )} - \frac{1}{x}) = \infty

x \to 1 - lim (\frac{1}{ln ( x )} - \frac{1}{x}) = - \infty

= diverges

x \to - 2 - lim (\frac{x ^{2}}{3 x + 6})

t \to 1 lim (t^{2})

x \to 4 lim (5 x + 2)

x \to - 3 lim (2 x)

x \to - 1 + lim (x + 1)

What is the limit as x approaches 1 of 1/(ln(x))-1/x ?
The limit as x approaches 1 of 1/(ln(x))-1/x is diverges