What is area y=sec^2(x),y=8cos(x),-pi/3 , pi/3 ?

The answer to area y=sec^2(x),y=8cos(x),-pi/3 , pi/3 is 10.39230…

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area y=sec^2(x),y=8cos(x),-pi/3 , pi/3

area

y = sec^{2} (x), y = 8 cos (x), - \frac{π}{3}, \frac{π}{3}

10.39230 \dots

Solution steps

Apply the area formula:

\int_{- \frac{π}{3}}^{\frac{π}{3}} sec^{2} (x) - 8 cos (x) d x

Solve

\int_{- \frac{π}{3}}^{\frac{π}{3}} sec^{2} (x) - 8 cos (x) d x : 10.39230 \dots

The area is:

= 10.39230 \dots

\int_{1}^{\infty} \frac{ln ( x )}{x ^{\frac{3}{2}}} d x

\frac{d}{d x} (1000 (1 + \frac{x}{12})^{60})

f (x) = (1 - x) (x^{2} - 7)^{2}

f (x) = x^{2} - x + 9, at x = 1

\frac{10}{s ( s ^{2} + 8 s + 25 )}

What is area y=sec^2(x),y=8cos(x),-pi/3 , pi/3 ?
The answer to area y=sec^2(x),y=8cos(x),-pi/3 , pi/3 is 10.39230…