What is the limit as x approaches pi of 2cos(x)+e^x ?

The limit as x approaches pi of 2cos(x)+e^x is -2+e^pi

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limit as x approaches pi of 2cos(x)+e^x

x \to π lim (2 cos (x) + e^{x})

- 2 + e^{π}

Decimal Notation

21.14069 \dots

Solution steps

x \to π lim (2 cos (x) + e^{x})

Plug in the value

x = π

= 2 cos (π) + e^{π}

2 cos (π) = - 2

= - 2 + e^{π}

x \to - 3 + lim (\frac{3 + x}{x})

x \to \infty lim (x^{2} + 3 x)

x \to - \infty lim (2 x + 5)

x \to (5, - 1) lim (x^{2} + y^{2})

x \to 0 lim (x sin^{2} (\frac{1}{x}))

What is the limit as x approaches pi of 2cos(x)+e^x ?
The limit as x approaches pi of 2cos(x)+e^x is -2+e^pi