What is the limit as x approaches 2 of (x^2+x)/(x-2) ?

The limit as x approaches 2 of (x^2+x)/(x-2) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 2 of (x^2+x)/(x-2)

x \to 2 lim (\frac{x ^{2} + x}{x - 2})

diverges

Solution steps

x \to 2 lim (\frac{x ^{2} + x}{x - 2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{x ^{2} + x}{x - 2}) = \infty

x \to 2 - lim (\frac{x ^{2} + x}{x - 2}) = - \infty

= diverges

x \to \infty lim ((\frac{14 x}{14 x + 6})^{2 x})

x \to 0 - lim (\frac{6}{5 x ^{3}})

x \to 0 - lim (\frac{1}{x ^{15}})

x \to - 2 lim (π)

x \to 3 lim (3 x + 5)

What is the limit as x approaches 2 of (x^2+x)/(x-2) ?
The limit as x approaches 2 of (x^2+x)/(x-2) is diverges