What is the limit as x approaches 3 of (x+3)/(x^2-9) ?

The limit as x approaches 3 of (x+3)/(x^2-9) is diverges

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limit as x approaches 3 of (x+3)/(x^2-9)

x \to 3 lim (\frac{x + 3}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{x + 3}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x + 3}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{x + 3}{x ^{2} - 9}) = - \infty

= diverges

\frac{2 s + 2}{s + 10}

x \to 1 - lim (\frac{- 1}{( x - 1 ) ^{\frac{2}{3}}})

\frac{\partial}{\partial y} (3 x^{2} - 2 y^{3} + 6 x y^{2} - 8)

x^{2} 1, 8

f (x) = \frac{3 x}{x - 2}, at a = 4

What is the limit as x approaches 3 of (x+3)/(x^2-9) ?
The limit as x approaches 3 of (x+3)/(x^2-9) is diverges