What is the limit as x approaches 2 of x/(x^3-8) ?

The limit as x approaches 2 of x/(x^3-8) is diverges

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limit as x approaches 2 of x/(x^3-8)

x \to 2 lim (\frac{x}{x ^{3} - 8})

diverges

Solution steps

x \to 2 lim (\frac{x}{x ^{3} - 8})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{x}{x ^{3} - 8}) = \infty

x \to 2 - lim (\frac{x}{x ^{3} - 8}) = - \infty

= diverges

x \to \frac{π ^{+}}{2} lim (tan (x))

x \to 0 lim (x^{2} \cdot csc^{2} (x))

x \to 0 lim (- x^{2} + 6 x - 8)

x \to - 1 lim (ln (x^{2}))

x \to \infty lim (\frac{8 x ^{2} - 3 x}{16 x ^{2} - 1})

What is the limit as x approaches 2 of x/(x^3-8) ?
The limit as x approaches 2 of x/(x^3-8) is diverges