What is the sum from n=1 to infinity of (2n)/(5n-4) ?

The sum from n=1 to infinity of (2n)/(5n-4) is diverges

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sum from n=1 to infinity of (2n)/(5n-4)

n = 1 \sum \infty \frac{2 n}{5 n - 4}

diverges

Solution steps

n = 1 \sum \infty \frac{2 n}{5 n - 4}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{n}{5 n - 4}

Apply Series Divergence Test:

diverges

= 2 diverges

= diverges

\int \frac{x ^{2} - 4}{x ^{6}} d x

y = x^{3} - 3 x^{2} + 25

\int_{0}^{π} 9 e^{x} sin (x) d x

\frac{d}{d x} (arctan (sec (x) + tan (x)))

y = \frac{sin ( x )}{x ^{2}}

What is the sum from n=1 to infinity of (2n)/(5n-4) ?
The sum from n=1 to infinity of (2n)/(5n-4) is diverges