What is the limit as x approaches 0 of 1/(x^{1/3)} ?

The limit as x approaches 0 of 1/(x^{1/3)} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 1/(x^{1/3)}

x \to 0 lim (\frac{1}{x ^{\frac{1}{3}}})

diverges

Solution steps

x \to 0 lim (\frac{1}{x ^{\frac{1}{3}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x ^{\frac{1}{3}}}) = \infty

x \to 0 - lim (\frac{1}{x ^{\frac{1}{3}}}) = - \infty

= diverges

x \to 0 + lim (\frac{x}{e ^{- \frac{9}{x}}})

x \to 0 + lim (tan (x^{x}))

x \to 1 lim ((x^{2} - 4) (x - 3))

x \to 0 - lim ((x - 5) e^{\frac{1}{x}})

x \to 0 lim (\frac{2 x}{x + 1})

What is the limit as x approaches 0 of 1/(x^{1/3)} ?
The limit as x approaches 0 of 1/(x^{1/3)} is diverges