What is area y= 1/2 x^3+2,y=-x+1,x=0,x=2 ?

The answer to area y= 1/2 x^3+2,y=-x+1,x=0,x=2 is 6

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area y= 1/2 x^3+2,y=-x+1,x=0,x=2

area

y = \frac{1}{2} x^{3} + 2, y = - x + 1, x = 0, x = 2

6

Solution steps

Apply the area formula:

\int_{0}^{2} \frac{1}{2} x^{3} + 2 - (- x + 1) d x

Solve

\int_{0}^{2} \frac{1}{2} x^{3} + 2 - (- x + 1) d x : 6

The area is:

= 6

t e^{- 3 t}

2 e^{3 t} sin (4 t)

\frac{d}{d x} (ln (x) csch (7 x))

\frac{\partial}{\partial x} (\frac{y}{x ^{2} + y ^{2}})

\int sin (x) + y d x

What is area y= 1/2 x^3+2,y=-x+1,x=0,x=2 ?
The answer to area y= 1/2 x^3+2,y=-x+1,x=0,x=2 is 6